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Math Help - v-t graph

  1. #1
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    v-t graph

    Could someone check this because I have different answers to those given for parts ii and iii.
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  2. #2
    MHF Contributor MarkFL's Avatar
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    Re: v-t graph

    i) You want to use a=\frac{\Delta v}{\Delta t}. Your result will be in \frac{\text{km}}{\text{min}\cdot\text{hr}}. To make the required conversion to the units given use:

    x\frac{\text{km}}{\text{min}\cdot\text{hr}}\cdot \frac{1000\text{ m}}{1\text{ km}}\cdot\frac{1\text{ hr}}{3600\text{s}}\cdot\frac{1\text{ min}}{60\text{ s}}=\frac{x}{216}\,\frac{\text{m}}{\text{s}^2}

    ii) The area under the velocity function is two right triangles, a trapezoid and a rectangle. Then divide the area by 60 to convert the minutes to hours to get the result in km.

    iii) Use \bar{v}=\frac{d}{t}
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  3. #3
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    Re: v-t graph

    The unit conversion has been tricky for me. Its not x/216 its 1000x/60^3. Your left hand side seems to be ok. I had not the trapezoid (trapezium to non americans).
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  4. #4
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    Re: v-t graph

    x/216 is equal to 1000x/60^3.
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