How much heat (kJ) is needed to raise the temperature of 100.0 grams of water from 25.0°C to 50.0°C?

Q=m x C x change in temp

Q= ?

m= 100.0g

C=?

tf 25.0 C - Ti 50.0 C

trouble setting this up

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- Dec 2nd 2012, 03:50 PMLouisana1Specific heat
How much heat (kJ) is needed to raise the temperature of 100.0 grams of water from 25.0°C to 50.0°C?

Q=m x C x change in temp

Q= ?

m= 100.0g

C=?

tf 25.0 C - Ti 50.0 C

trouble setting this up

- Dec 2nd 2012, 03:59 PMjakncokeRe: Specific heat
$\displaystyle Q = 4.8 \frac{J}{g C} * 100 \frac{g}{ml} * 25 C $

about 12 KJ - Dec 2nd 2012, 04:35 PMLouisana1Re: Specific heat
I came up with q= 100.0 x 4.18 x 25.0

10450.

10.5 kj - Dec 2nd 2012, 04:36 PMjakncokeRe: Specific heat