I have few probs i need to help with here are cupple i did them on photoshop heres the link to it CLICK HERE TO SEE THE PROBS

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- Mar 5th 2006, 09:27 AMautopimpNeed Help!
I have few probs i need to help with here are cupple i did them on photoshop heres the link to it CLICK HERE TO SEE THE PROBS

- Mar 5th 2006, 11:13 AMThePerfectHacker
Problem 3]

Multiply by Common Denominator to get,

, thus,

Thus,

Thus,

Thus,

Thus,

- Mar 5th 2006, 11:38 AMThePerfectHacker
Problem 4]

Open parantheses,

Use rule of exponents,

Use rule of exponents again ( ),

Q.E.D. - Mar 5th 2006, 11:40 AMThePerfectHacker
Problem 5]

Q.E.D. - Mar 5th 2006, 11:45 AMtopsquarkQuote:

Originally Posted by**autopimp**

Solve by substitution:

In the substitution method we solve one of the equations for one unknown and plug it into the other...this creates an equation with only one unknown in it. I tend to pick the simplest variable to solve for. In this case that looks to be the x in the second equation.

So solving the second equation for x I get:

Plugging this value of x into the first equation I get:

.

I'll let you take it from here. You may plug this value of y into any of the original equations, or more simply, into your x equation. I get (x,y) = (5,-1).

-Dan - Mar 5th 2006, 11:57 AMearbothQuote:

Originally Posted by**autopimp**

to problem nr. 6: Transform the quotient into a product:

factorize all numerators and denominators:

simplify and you'll get:

Greetings

EB - Mar 5th 2006, 12:03 PMearbothQuote:

Originally Posted by**autopimp**

to problem nr. 8:

Calculate the roots partially:

Greetings

EB