question 5 in the attached pdf.. Please explain.. I know you get to a point where it is the sq root of -11 but idk what to do after this . Please help
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$\displaystyle \displaystyle \begin{align*} \sqrt{-11} = \sqrt{-1 \cdot 11} = \sqrt{-1} \cdot \sqrt{11} = i\sqrt{11} \end{align*}$
Not a graded assignment. -Dan
Last edited by topsquark; Nov 8th 2012 at 09:00 AM.
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