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**Louisana1** A blue sports car (m=1200-kg) traveling north at 14 m/s is rear-ended by a 2000-kg truck traveling north at 25 m/s. If the truck and car locks bumpers and stick together, what is their speed immediately after the collision?

a. What is the momentum of the car BEFORE the collison

b. What is the momentum of the truck BEFORE the collision?

c. What is the total momentum BEFORE the collision?

d. What is the total momentum AFTER the collison?

e. What is the velocity of the cars after the collison?

Need help with the equations used in this

In the law of conservation of momentum we believe! Therefore the momentum in our system is the before and after the crash. Define an x-axis that is positive in the northern direction. The momentum of the car before the crash isp = mv => p = 1200*14 = 16800 kg*m/s due north

And the momentum for the truck before the crash is p = mv => p = 2000*25 = 50000 kg*m/s due north

The total momentum in the system before the crash is thereforep_tot = p_car+p_truck => p_tot = 16800+50000 = 66800 kg*m/s due north

Due the law of conservation of momentum we have this momentum after the crash as well. And we also know that the speed of the car and the truck is the same. Hence the momentum afterwards can be described asp_tot = (m_car+m_truck)v => 66800 = 3200*v <=> v ≈ 21 m/s due north