1. ## error analysis

p = ab
where a = 271.00 +- 0.005m
and b = 51.0 +- 0.05m find the maximum error.

is it right to calculate this by $\displaystyle (.005/271 + .05/51) * (271*51)$

2. yes that is correct.

3. Originally Posted by helmszee
p = ab
where a = 271.00 +- 0.005m
and b = 51.0 +- 0.05m find the maximum error.

is it right to calculate this by $\displaystyle (.005/271 + .05/51) * (271*51)$
It depends on what you mean by maximum error.

271.005 * 51.05 = 13834.8

and this is the largest value the product can take.

The smallest value it can take is:

270.995 * 50.95 = 13807.2

So these two represent errors of +/-13.8

RonL