F = mg => F = 2*10 = 20 N
The friction needs to be as large as the gravitational force, so that the packet won't move anywhere. The force by the friction is proportional to the normal force by the factor of coef of friction. That we have
F = μN <=> N = F/μ => N = 20/0.3 ≈ 67 N or with correct significant figures 0.07 kN.