Hello, Regarding, Solve for x, Log(base2)x + Log(base3)x = 1 I keep getting x = sq root of 6. The answer at the back of the book say x = 1.53. Is the book wrong? / what am I missing? Thank you, Gary Og.
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Originally Posted by GaryOg Hello, Regarding, Solve for x, Log(base2)x + Log(base3)x = 1 I keep getting x = sq root of 6. The answer at the back of the book say x = 1.53. Is the book wrong? / what am I missing? Thank you, Gary Og. Since I don't know what you did, I can't say where you went wrong. I get the exact answer as I would try by converting everything to a base 10 logarithm Now try to use the log properties to finish
Hello, GaryOg! I used the Base-Change Formula: . The equation becomes: . Multiply by . . . . . . . . . . . . . . . . . . . . . . Therefore: .
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