Edit: the questions it was asking
Vector A has y - component Ay = +12.0m A makes an angle 32.0 degrees counterclockwise from the + y - axis.
How do you do this more likely how do you draw this.
What is the x-component of vector A?
What is the magnitude of vector A?
So draw your Cartesian axes, and draw a vector that makes an angle of 32 degrees counterclockwise from the positive y axis. Make it so that it reaches up as high as 12 units on your y axis. Can you see the right angle triangle? Can you use trigonometry to evaluate the horizontal distance (x component) and the hypotenuse (magnitude)?
First, since the angle is "counterclockwise from the positive y axis", the x component will be negative. Ignoring the sign, you have a right triangle with angle 32 degrees, "near side" of length 12, and "opposite side" of unknown length x. "Tan= Opposite side over near side" gives x/12= tan(32).