Another Physics problem

**Louisana1** · September 26th 2012, 11:48 AM

A car initially traveling westward at 20 m/s has a constant acceleration of 1 m/s^2 eastward. How far does the car travel in the first 10 s?

Help!!!!

**MarkFL** · September 26th 2012, 11:54 AM

Hint: $x(t)=\frac{1}{2}at^2+v_0t$

**Louisana1** · September 26th 2012, 11:55 AM

After 10 seconds, the speed of the car is v = u + at = 20 + (-1)*10 = 10 m/s

The distance travelled is S = 1/2 * (u + v) * t = 0.5*(20+10)*10 = 150 m

**Louisana1** · September 26th 2012, 12:00 PM

Hey LOL is this right? I did mines a different way

**MarkFL** · September 26th 2012, 03:10 PM

Yes, the kinematic equation I cited returns the same value:

$x(10)=\frac{1}{2}(-1)(10)^2+20(t)=-50+200=150$

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