
Physics
Three forces act on an object. A 3 N force acts due east and a 6 N force acts due north. If the net force on the object is zero, what is the magnitude of the third force?
What is the equation for this? I have been trying to work this out for 40mins?

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Re: Physics
$\displaystyle \sum F_x = 0$
$\displaystyle \sum F_y = 0$
you have a 3N force east ... has to be balanced by a 3N force west
you have a 6N force north ... has to be balanced by a 6N force south
this says the 3rd force has a west component of 3N and a south component of 6N ... resolve the components.

Re: Physics
Skeeter do you know where I can find a video or examples like this problem? I am like totally lost.

Re: Physics

Re: Physics
I still got stuck on this problem so I asked the instructor, but no help really he was pretty busy. He did give me this but have no clue how he got it.
A+B magnitude = sqrt(6^2 + 3^2) = 6.71
How the heck did he get this? I am putting the numbers in the calculator and not coming up with 6.71

Re: Physics
he's using Pythagoras ... and you must be entering the info in your calculator incorrectly
$\displaystyle \sqrt{6^2+3^2} = \sqrt{36+9} = \sqrt{45} \approx 6.71$