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Math Help - First time user-need help in linear expressions

  1. #1
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    First time user-need help in linear expressions Please help Urgent

    How do i find the x and the y-int of these;

    a. y=4x-8

    b. 3x-2y+6=0

    Please show full steps!
    Thank you so much!
    Last edited by cheers; September 25th 2012 at 01:45 PM.
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  2. #2
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    Re: First time user-need help in linear expressions

    First time user-need help in linear expressions-intercepts.gif

    (a) y = 4x - 8

    You find y-intercepts where x=0. Points look like (0,yInt).
    Plugging in:
    (yInt) = 4(0) - 8
    Solves yInt = -8.
    Y-intercept is the point (0, -8).

    You find x-intercepts where y=0. Points look like (xInt, 0).
    Plugging in:
    (0) = 4(xInt) - 8
    so 4(xInt) - 8 = 0
    so 4(xInt) = 8
    so xInt = 8/4 = 2
    Solves xInt = 2.
    X-intercept is the point (2, 0).

    Part (b) is done the same way.
    Thanks from cheers
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  3. #3
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    Re: First time user-need help in linear expressions

    Thank you so much!
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  4. #4
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    Re: First time user-need help in linear expressions

    You can solve these types of equation by transferring all the variable one side & constant on the other side of equal. So,
    a.) y=4x-8
    =>4x-y=8 ------------(i)
    b.) 3x-2y+6=0
    =>b. 3x-2y=-6 ----------(ii)
    Now solve both equations & get the value of x & y
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