Thread: First time user-need help in linear expressions

How do i find the x and the y-int of these;

a. y=4x-8

b. 3x-2y+6=0

Please show full steps!
Thank you so much!

(a) y = 4x - 8

You find y-intercepts where x=0. Points look like (0,yInt).
Plugging in:
(yInt) = 4(0) - 8
Solves yInt = -8.
Y-intercept is the point (0, -8).

You find x-intercepts where y=0. Points look like (xInt, 0).
Plugging in:
(0) = 4(xInt) - 8
so 4(xInt) - 8 = 0
so 4(xInt) = 8
so xInt = 8/4 = 2
Solves xInt = 2.
X-intercept is the point (2, 0).

Part (b) is done the same way.

Thank you so much!

You can solve these types of equation by transferring all the variable one side & constant on the other side of equal. So,
a.) y=4x-8
=>4x-y=8 ------------(i)
b.) 3x-2y+6=0
=>b. 3x-2y=-6 ----------(ii)
Now solve both equations & get the value of x & y