How do i find the x and the y-int of these;
a. y=4x-8
b. 3x-2y+6=0
Please show full steps!
Thank you so much!
(a) y = 4x - 8
You find y-intercepts where x=0. Points look like (0,yInt).
Plugging in:
(yInt) = 4(0) - 8
Solves yInt = -8.
Y-intercept is the point (0, -8).
You find x-intercepts where y=0. Points look like (xInt, 0).
Plugging in:
(0) = 4(xInt) - 8
so 4(xInt) - 8 = 0
so 4(xInt) = 8
so xInt = 8/4 = 2
Solves xInt = 2.
X-intercept is the point (2, 0).
Part (b) is done the same way.
You can solve these types of equation by transferring all the variable one side & constant on the other side of equal. So,
a.) y=4x-8
=>4x-y=8 ------------(i)
b.) 3x-2y+6=0
=>b. 3x-2y=-6 ----------(ii)
Now solve both equations & get the value of x & y