How do i find the x and the y-int of these;

a. y=4x-8

b. 3x-2y+6=0

Please show full steps!

Thank you so much!

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- September 25th 2012, 01:07 PMcheersFirst time user-need help in linear expressions Please help Urgent
How do i find the x and the y-int of these;

a. y=4x-8

b. 3x-2y+6=0

Please show full steps!

Thank you so much! - September 25th 2012, 02:22 PMjohnsomeoneRe: First time user-need help in linear expressions
Attachment 24928

(a) y = 4x - 8

You find y-intercepts where x=0. Points look like (0,yInt).

Plugging in:

(yInt) = 4(0) - 8

Solves yInt = -8.

Y-intercept is the point (0, -8).

You find x-intercepts where y=0. Points look like (xInt, 0).

Plugging in:

(0) = 4(xInt) - 8

so 4(xInt) - 8 = 0

so 4(xInt) = 8

so xInt = 8/4 = 2

Solves xInt = 2.

X-intercept is the point (2, 0).

Part (b) is done the same way. - September 25th 2012, 02:23 PMcheersRe: First time user-need help in linear expressions
Thank you so much!

- September 26th 2012, 12:03 AMkraj8995Re: First time user-need help in linear expressions
You can solve these types of equation by transferring all the variable one side & constant on the other side of equal. So,

a.) y=4x-8

=>4x-y=8 ------------(i)

b.) 3x-2y+6=0

=>b. 3x-2y=-6 ----------(ii)

Now solve both equations & get the value of x & y