# First time user-need help in linear expressions

• Sep 25th 2012, 02:07 PM
cheers
How do i find the x and the y-int of these;

a. y=4x-8

b. 3x-2y+6=0

Thank you so much!
• Sep 25th 2012, 03:22 PM
johnsomeone
Re: First time user-need help in linear expressions
Attachment 24928

(a) y = 4x - 8

You find y-intercepts where x=0. Points look like (0,yInt).
Plugging in:
(yInt) = 4(0) - 8
Solves yInt = -8.
Y-intercept is the point (0, -8).

You find x-intercepts where y=0. Points look like (xInt, 0).
Plugging in:
(0) = 4(xInt) - 8
so 4(xInt) - 8 = 0
so 4(xInt) = 8
so xInt = 8/4 = 2
Solves xInt = 2.
X-intercept is the point (2, 0).

Part (b) is done the same way.
• Sep 25th 2012, 03:23 PM
cheers
Re: First time user-need help in linear expressions
Thank you so much!
• Sep 26th 2012, 01:03 AM
kraj8995
Re: First time user-need help in linear expressions
You can solve these types of equation by transferring all the variable one side & constant on the other side of equal. So,
a.) y=4x-8
=>4x-y=8 ------------(i)
b.) 3x-2y+6=0
=>b. 3x-2y=-6 ----------(ii)
Now solve both equations & get the value of x & y