Suppose 12 g of natural gas combines with 48 g of oxygen in a flame. The chemical change produces 33 g of carbon dioxide. How many grams of water form?
33-48+12=27g
I know this but is there an equation for this
Conversion of Energy UnitsThe complete combustion of a small wooden match produces approximately 512 cal of heat. How many kilojoules are produced?
Is there an equation for this..The instructor says answer is 2.14 kJ
Ok i figured out this
512cal x 4.184J/cal = 2.14
Yep:
CH4 + 2O2 --> CO2 + 2H20
The molecular weights of this reaction can be calculated using molecular weights of the constituent atoms: H=1, C=12, and O=16:
(12+4) + 2(16x2) --> 12+2(16) + 2(2x1 + 16),
16 + 64 --> 44 + 36,
80 --> 80
If you multiply each of thee by 3/4 you get the proportions youi asked about:
12 + 48 = 33 + 27