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Math Help - Conservation of Mass

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    Conservation of Mass

    Suppose 12 g of natural gas combines with 48 g of oxygen in a flame. The chemical change produces 33 g of carbon dioxide. How many grams of water form?

    33-48+12=27g

    I know this but is there an equation for this
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    Re: Conservation of Mass

    Quote Originally Posted by Louisana1 View Post
    33-48+12=27g
    33 - 48 + 12 ≠ 27.
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    Re: Conservation of Mass

    Conversion of Energy UnitsThe complete combustion of a small wooden match produces approximately 512 cal of heat. How many kilojoules are produced?

    Is there an equation for this..The instructor says answer is 2.14 kJ


    Ok i figured out this

    512cal x 4.184J/cal = 2.14
    Last edited by Louisana1; September 19th 2012 at 08:38 AM.
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    Re: Conservation of Mass

    Convert 2.75 x 10^4 kJ to calories
    How is this figured out. Worded crazy to me

    answer is this says my ughh instructor 6.57 x 10^6 cal
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    Re: Conservation of Mass

    Quote Originally Posted by Louisana1 View Post
    Convert 2.75 x 10^4 kJ to calories
    How is this figured out. Worded crazy to me

    answer is this says my ughh instructor 6.57 x 10^6 cal
    How many groups of 4.184J (i.e., calories) are contained in 2.75 x 104kJ = 2.75 x 107J?
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    Re: Conservation of Mass

    Quote Originally Posted by Louisana1 View Post
    Suppose 12 g of natural gas combines with 48 g of oxygen in a flame. The chemical change produces 33 g of carbon dioxide. How many grams of water form?

    33-48+12=27g

    I know this but is there an equation for this
    Yep:

    CH4 + 2O2 --> CO2 + 2H20

    The molecular weights of this reaction can be calculated using molecular weights of the constituent atoms: H=1, C=12, and O=16:

    (12+4) + 2(16x2) --> 12+2(16) + 2(2x1 + 16),
    16 + 64 --> 44 + 36,
    80 --> 80

    If you multiply each of thee by 3/4 you get the proportions youi asked about:

    12 + 48 = 33 + 27
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