Results 1 to 2 of 2

Math Help - physics: two cars traveling question

  1. #1
    Senior Member
    Joined
    Jan 2007
    Posts
    477

    physics: two cars traveling question

    There are Two cars, A and B that are traveling in the same direction, although car A is 193 m behind car B. The speed of A is 27.1 meters per second, and the speed of B is 18.6 meters per seconds. How much time does it take for A to catch B?

    in seconds?

    anyone who can help me with this please.
    Follow Math Help Forum on Facebook and Google+

  2. #2
    MHF Contributor
    Joined
    Apr 2005
    Posts
    1,631
    For A to catch B, A must travel (193 +x) meters if B travels x meters, both spending the same amount of time.

    Distance = speed * time
    So, time = distance / speed
    t1 = t of A = (193 +x)/27.1
    t2 = t of B = x/18.6

    t1 = t2
    (193 + x)/27.1 = x/18.6
    Cross multiply,
    (193 +x)(18.6) = 27.1(x)
    193(18.6) +18.6x = 27.1x
    193(18.6) = 27.1x -18.6x = 8.5x
    x = (193*18.6)/8.5 = 422.33 m

    Hence,
    t = t1 = (193 +422.33)/27.1 = 22.7 sec
    t = t2 = 422.33/18.6 = 22.7 sec

    Therefore, after 22.7 seconds, A will catch up with B. -----answer.
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Got a physics question or interested in physics?
    Posted in the Math Topics Forum
    Replies: 16
    Last Post: February 3rd 2014, 02:56 AM
  2. Traveling
    Posted in the Pre-Calculus Forum
    Replies: 3
    Last Post: November 27th 2009, 07:41 PM
  3. Cars
    Posted in the Pre-Calculus Forum
    Replies: 1
    Last Post: June 13th 2007, 07:59 PM
  4. Registration of cars
    Posted in the Statistics Forum
    Replies: 5
    Last Post: March 9th 2007, 11:18 PM
  5. traveling car
    Posted in the Algebra Forum
    Replies: 2
    Last Post: October 31st 2005, 04:18 AM

Search Tags


/mathhelpforum @mathhelpforum