Did not know if it was right
Last edited by Louisana1; September 18th 2012 at 10:28 AM.
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Why did you write the problem two times? Originally Posted by Louisana1 When 47.5 J of heat are added to 13.2 g of a liquid, its temperature raises by 1.72 degree Celsius. What is the heat capacity of the liquid?
Q· m·Δt=c This last equation obviously should be c = Q / (m · Δt). Originally Posted by Louisana1 C= 47.5 joules
13.2 g x 1.72°c
C = 2.09 joules
g °c The answer is correct, but please write expressions in one line and use parentheses to change the order of operations, e.g., C = 2.09 J / (g · °C).
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