Thread: Chemistry heat

Did not know if it was right

Why did you write the problem two times?

Originally Posted by Louisana1

When 47.5 J of heat are added to 13.2 g of a liquid, its temperature raises by 1.72 degree Celsius. What is the heat capacity of the liquid?

Q=m·c·Δt

Q· m·Δt=c

This last equation obviously should be c = Q / (m · Δt).

Originally Posted by Louisana1

C= 47.5 joules
13.2 g x 1.72°c

C = 2.09 joules
g °c

The answer is correct, but please write expressions in one line and use parentheses to change the order of operations, e.g., C = 2.09 J / (g · °C).