1. ## Chemisty confusions

When 47.5 J of heat are added to 13.2 g of a liquid, its temperature raises by 1.72 degree Celsius. What is the heat capacity of the liquid?

Chemistry

3. ## Re: Chemisty confusions

Originally Posted by Louisana1
When 47.5 J of heat are added to 13.2 g of a liquid, its temperature raises by 1.72 degree Celsius. What is the heat capacity of the liquid?
I think that if you were to look up the definition of "heat capacity" that would make what you need to do clear.

4. ## Re: Chemisty confusions

I am still having issues placing these numbers in the correct spot. Is there anyone that can point me in the right direction, or share some links that would help me with this further.

5. ## Re: Chemisty confusions

$Q = m \cdot C \cdot \Delta T$

you are given $Q$ , $m$ , and $\Delta T$ ... solve for $C$

6. ## Re: Chemisty confusions

47.5J(13.2g)(4.18j)(1.72c)= 341.506 grams
signif digits 341.5

Is this right?

7. ## Re: Chemisty confusions

Q=m·c·Δt
47.5 joules = 13.2g·4.18Joules·1.72°c
47.5 = 94.90272g

Do I divide this I'm not sure if this is right?Can someone point me in the right direction?

8. ## Re: Chemisty confusions

$Q = m \cdot C \cdot \Delta T$

$\frac{Q}{m \cdot \Delta T} = C$

substitute in your given values and calculate the specific heat, C.