Chemisty confusions

• Sep 16th 2012, 11:20 AM
Louisana1
Chemisty confusions
When 47.5 J of heat are added to 13.2 g of a liquid, its temperature raises by 1.72 degree Celsius. What is the heat capacity of the liquid?
• Sep 16th 2012, 11:23 AM
skeeter
Re: Chemisty confusions
• Sep 16th 2012, 11:39 AM
HallsofIvy
Re: Chemisty confusions
Quote:

Originally Posted by Louisana1
When 47.5 J of heat are added to 13.2 g of a liquid, its temperature raises by 1.72 degree Celsius. What is the heat capacity of the liquid?

I think that if you were to look up the definition of "heat capacity" that would make what you need to do clear.
• Sep 16th 2012, 06:26 PM
Louisana1
Re: Chemisty confusions
I am still having issues placing these numbers in the correct spot. Is there anyone that can point me in the right direction, or share some links that would help me with this further.
• Sep 16th 2012, 06:43 PM
skeeter
Re: Chemisty confusions
$Q = m \cdot C \cdot \Delta T$

you are given $Q$ , $m$ , and $\Delta T$ ... solve for $C$
• Sep 16th 2012, 07:11 PM
Louisana1
Re: Chemisty confusions
47.5J(13.2g)(4.18j)(1.72c)= 341.506 grams
signif digits 341.5

Is this right?
• Sep 16th 2012, 07:37 PM
Louisana1
Re: Chemisty confusions
Q=m·c·Δt
47.5 joules = 13.2g·4.18Joules·1.72°c
47.5 = 94.90272g

Do I divide this I'm not sure if this is right?Can someone point me in the right direction?
• Sep 17th 2012, 04:06 AM
skeeter
Re: Chemisty confusions
$Q = m \cdot C \cdot \Delta T$

$\frac{Q}{m \cdot \Delta T} = C$

substitute in your given values and calculate the specific heat, C.