There is a number 2^n. when its digits are reversed it becomes 2^m.Find the least possible value of n.
Hello, geniusgarvil!
Where did this problem come from?
$\displaystyle \text{There is a number }2^n.\;\text{When its digits are reversed it, becomes }2^m.$
$\displaystyle \text{Find the least possible value of }n.$
We want a power-of-two which is the reversal of a power-of-two.
Without initiating a computer search,
. . it seems that only answers are one-digit values.
I am not getting this , you should discuss problem with good theory so I can give a better solution. in my opinion power of integer shows it's multiple and it's a short form of any large number most probably used in algebra, linear equation and differential equation problems.how to do pre algebra