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Thread: Momentum

  1. #1
    Member srirahulan's Avatar
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    Lightbulb Momentum

    Hi Guys, I have question on momentum.

    A 2000 kg automobile going east on chestnut street at 60mi/hr collides with a 4000kg truck which is going south across chestnut street at 20mi/hr.If they become coupled
    on collision, what is the magnitude and direction of their velocity immediately after colliding?

    In this case we want to use conservation of linear Momentum.But i have a struggle on their velocity because it is a vector equation, So how can i find their velocity in proper way.
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  2. #2
    Member srirahulan's Avatar
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    Re: Momentum

    can any one understand my problem?
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  3. #3
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    Re: Momentum

    Quote Originally Posted by srirahulan View Post
    can any one understand my problem?
    momentum is conserved in both the x and y directions
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  4. #4
    Member srirahulan's Avatar
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    Re: Momentum

    Thanks for your solution but,How can i apply the equation for that.
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  5. #5
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    Re: Momentum

    Quote Originally Posted by srirahulan View Post
    Thanks for your solution but,How can i apply the equation for that.
    in the x-direction ...

    $\displaystyle p_x_0 = p_x_f$

    $\displaystyle 2000(60) = (2000+4000)v_x_f$


    in the y-direction ...

    $\displaystyle p_y_0 = p_y_f$

    $\displaystyle 4000(-20) = (2000+4000)v_y_f$


    ... solve for the final velocity using the equations for each component of final velocity determined by the conservation of momentum equations above.
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