V=40+i35volts
I=6+i3amps
i have worked out that the phase difference between V and I is A= 14.6degrees
converted V and I into polar form V= 53.2/41.2degrees I=6.8/26.6degrees now find the power(watt) Power=(V) X( I )X (cosA)
(V)X(I)=361/67.8degrees in polar form
can anyone please explain how i multiply a polar number by cos14.6 or have i gone wrong somewhere?