V=40+i35volts

I=6+i3amps

i have worked out that the phase difference between V and I is A= 14.6degrees

converted V and I into polar form V= 53.2/41.2degrees I=6.8/26.6degrees now find the power(watt) Power=(V) X( I )X (cosA)

(V)X(I)=361/67.8degrees in polar form

can anyone please explain how i multiply a polar number by cos14.6 or have i gone wrong somewhere?