This means, when C increases by 1, F increases by 9/5. And yes, the units will be
Well I have a problem, about how when celsius increases, the fahrenheit will increase as well.
I have a graph, showing my celcius as the manipulative variable (on the x-axis), while the fahrenheit is the responding variable (y-axis)
So I used the slope equation, m=(change in y)/(change in x)
So I grabbed 2 points and did m=(212^{o}F-50^{o}F)/(100^{o}C-10^{o}C) = 162^{o}F/90^{o}C
I know that 162/90 = 1.80
But I have 2 different units in the final solution, fahrenhait (^{o}F) and celcius (^{o}C)
I always have to include the units so that when another person reads it, they would know what units I am talking about.
So can anyone explain to me which units I would use? I wasn't sure to convert one measurement to another, cause that would start messing things up maybe.
Ok thanks!
So once I try to find points on the graph, like an x coordinate or y coordinate.
If I plug it into the linear equation: y=mx+b
and since m=1.80^{o}F/^{o}C
If I had to subtract it from Fahrenheit, how will the units become then?
Since if I subtract m, into y so I could get x, y is Fahrenheit, while m is Fahrenheit over Celsius.
Can anyone explain? Thanks
Thanks!
I saw where my mistakes were now!
So just wondering, if I was looking for an x coordinate, and I got a y coordinate, for example:
I know Y = 70^{o}F
So I put it into the linear equation
1. 70^{o}F=(9^{o}F/5^{o}C)x + 32^{o}F
2. 350^{o}F^{o}C = (9^{o}F)x + 32^{o}F Multiply both sides by 5^{o}C
3. 38.88^{o}C = x + 32^{o}F Divide both sides by 9^{o}F
So I got 2 numbers equaled to each other, but they're both different units.
Did I do something wrong or should I subtract 32 from both sides to find x?
Thanks