Thank you, it is so easy when you can see it.
I appreciate your patience
If you set a = 0.7m/s^2 and solve for t1 and t2 then the result is:
t1 = 0.5208 seconds
d1 = 0.147m
v_c = 0.464 m/s
t2 = 0.6065 seconds
d2 = 0.153m
T_total = 1.127 second
In reviewing my previous posts with the solution to your first question I see that I made a typo, which I have corrected in bold font below:
wow glad you spotted that I am going to motion trials tomorrow.
Bit of difference between 0.818 m/s^2 and 0.818s
Thing is without thinking I used the result as acceleration and calculated the time and distance from it.
It was movable and never hit limits.
I never twigged but might have tomorrow when the machine pulled itself off the floor!