
Integration
Given that $\displaystyle f(x\frac{1}{2})f(x\frac{1}{4}) = 0$ for all real numbers $\displaystyle x $and $\displaystyle \int_0^1 f(x)= c. Find \int_1^2 f(x)\,dx.\ + \int_2^4 f(2x)\,dx.\ + \int_4^8 f(4x)\,dx.$. Can someone pls explain what this problem means and how to solve it?? Thanks in advance.

Re: Integration
Hi, shiny718. Is the answer 73c perhaps? If it is I'll explain what's going on. I don't want to give you a detailed explanation that ends up being wrong because that usually creates more confusion than clarity.