# Probability combinations help!

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• Jul 24th 2012, 02:13 PM
lucak
Probability combinations help!
Please help,
What is the probability of having two aces, two kings, and a queen in a five‐card poker hand?

,Thanks
• Jul 24th 2012, 02:25 PM
Plato
Re: Probability combinations help!
Quote:

Originally Posted by lucak
What is the probability of having two aces, two kings, and a queen in a five‐card poker hand?

There are $\binom{4}{2}\binom{4}{2}\binom{4}{1}$ ways to have two aces, two kings, and a queen in a five‐card poker hand.
• Jul 24th 2012, 02:39 PM
lucak
Re: Probability combinations help!
Quote:

Originally Posted by Plato
There are $\binom{4}{2}\binom{4}{2}\binom{4}{1}$ ways to have two aces, two kings, and a queen in a five‐card poker hand.

I understand how you got that that part I get but the answer in the back of the book was (4combination2)(4combination2)(4combination1) that was in the numerator. Then in the denominator it was 52combination5 and the answer was 3 over 216580. I don't understand how they got that answer
• Jul 24th 2012, 02:43 PM
Plato
Re: Probability combinations help!
Quote:

Originally Posted by lucak
I understand how you got that that part I get but the answer in the back of the book was (4combination2)(4combination2)(4combination1) that was in the numerator. Then in the denominator it was 52combination5 and the answer was 3 over 216580. I don't understand how they got that answer

Do you understand that $\binom{N}{k}=\frac{N!}{k!(N-k)!}~?$
• Jul 24th 2012, 04:09 PM
lucak
Re: Probability combinations help!
Quote:

Originally Posted by Plato
Do you understand that $\binom{N}{k}=\frac{N!}{k!(N-k)!}~?$

Yes I understand that, but how did they get 3 as the top numerator?
• Jul 24th 2012, 04:40 PM
Plato
Re: Probability combinations help!
Quote:

Originally Posted by lucak
Yes I understand that, but how did they get 3 as the top numerator?

You do not. Your textbook is wrong. $\dfrac{\dbinom{4}{2}\dbinom{4}{2}\dbinom{4}{1}} {\dbinom{52}{5}}=\frac{10673}{192629862}}$.