Results 1 to 6 of 6

Math Help - Division problem, I need help please?

  1. #1
    Junior Member Subliminalmessage's Avatar
    Joined
    Jun 2012
    From
    Liverpool
    Posts
    28

    Division problem, I need help please?

    Hello guys, Iíve got another problem.


    Iím dividing 575 by 23 using the long division method.
    25

    23/575
    46
    115
    575
    -460
    So, Iíll tell you how I worked this out in case it was a problem with my working out.

    I asked myself the following, how many times does 23 go into 5 it does not, therefore how many times does 23 go into 57, it goes in 2 times. So, I put the 2 on top of the 7.

    Now, Iíve got to ask myself, 2 x 23 = 46 and then I put the 46 under the 23 and subtract 57 Ė 46 = 11, so I put 11 under the 46.

    GO RUNNING


    Then I bring the 5 down next to the 11 making 115.

    I then ask myself how many times 23 goes into 115 well it goes in exactly 5 times. So I put the 5 on the answer column next to the 2.

    I then do 25 x 23 = 575 and now the point where am stuck, Iíve got 115 Ė 575 = -460.


    So the answer is 25 remainder -460?


    Please can somebody help me out here?
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Member
    Joined
    Jan 2010
    Posts
    106
    Thanks
    2

    Re: Division problem, I need help please?

    Quote Originally Posted by Subliminalmessage View Post
    ...

    I then do 25 x 23 = 575 and now the point where am stuck, Iíve got 115 Ė 575 = -460.

    ...
    You only need to multiply 5 x 23, not the entire running quotient, so 5 x 23 = 115

    Follow Math Help Forum on Facebook and Google+

  3. #3
    Super Member

    Joined
    May 2006
    From
    Lexington, MA (USA)
    Posts
    11,739
    Thanks
    645

    Re: Division problem, I need help please?

    Hello, Subliminalmessage!

    You have invented a new (and incorrect) method of division.


    This reminds me of an old Abbott and Costello routine.

    Lou Costello insists that: 5 \times 14 \,=\,25.

    Bud Abbott tries to correct him, but Lou "proves" it.


    On a blackboard, he writes: . \begin{array}{ccc}1&4  \\ \times & 5 \\ \hline \end{array}

    He says, "Five time four is twenty": . \begin{array}{ccc}1&4 \\ \times & 5 \\ \hline 2 & 0 \end{array}

    Then "Five times one is five": . \begin{array}{ccc}1&4 \\ \times &5 \\ \hline 2&0 \\ & 5 \end{array}

    And before Bud can object, Lou draws the line and adds: / \begin{array}{cc}1&4 \\ \times & 5 \\ \hline 2 & 0 \\ & 5 \\ \hline 2 & 5 \end{array}
    "See?"


    Bud says, "You can't multiply like that! .What if you add five 14's?"

    Lou writes:. . \begin{array}{ccc}&1&4 \\ &1&4 \\ &1&4 \\ &1&4 \\+ &1&4 \\ \hline \end{array}


    Bud takes the chalk and adds up the right column: "4, 8, 12, 16, 20 ..."

    Lou pushes him aside and adds the down the left column: "21, 22, 23, 24, 25 !"

    And has: . \begin{array}{ccc}&1&4 \\ &1&4\\&1&4\\&1&4\\+&1&4\\ \hline & 2&5 \end{array}


    Bud complains again and asks "Okay, what is 25 divided by 5?"

    Lou write: . \begin{array}{cccc}&& - & - \\ 5 & ) & 2 & 5 \end{array}

    He says, "5 doesn't go into 2, but 5 goes into 5 once": . \begin{array}{cccc}&&& 1 \\ && - & - \\ 5 & ) & 2 & 5 \end{array}

    "One times five is five": . \begin{array}{cccc}&&&1 \\ && - & - \\ 5 & ) & 2 & 5 \\ &&&5 \end{array}

    "25 minus 5 is 20": . \begin{array}{cccc}&&&1 \\ && - & - \\ 5 & ) & 2 & 5 \\ &&& 5 \\ &&- & - \\ && 2 & 0 \end{array}

    "And 5 goes into 20 four times": . \begin{array}{ccccc}&&&1 & 4 \\ && - & - & - \\ 5 & ) & 2 & 5 \\  &&& 5 \\ & & - & - \\ & & 2 & 0 \\ && 2 & 0 \\ && - & - \\ \end{array}


    And Bud Abbott gives up . . .
    Follow Math Help Forum on Facebook and Google+

  4. #4
    Junior Member Subliminalmessage's Avatar
    Joined
    Jun 2012
    From
    Liverpool
    Posts
    28

    Re: Division problem, I need help please?

    Quote Originally Posted by daigo View Post
    You only need to multiply 5 x 23, not the entire running quotient, so 5 x 23 = 115

    Ha ha, damn I can be stupid sometimes. Thank you very much for a nice and simple answer, it helps when you draw it out like that.
    Follow Math Help Forum on Facebook and Google+

  5. #5
    Junior Member Subliminalmessage's Avatar
    Joined
    Jun 2012
    From
    Liverpool
    Posts
    28

    Re: Division problem, I need help please?

    Quote Originally Posted by Soroban View Post
    Hello, Subliminalmessage!

    You have invented a new (and incorrect) method of division.


    This reminds me of an old Abbott and Costello routine.

    Lou Costello insists that: 5 \times 14 \,=\,25.

    Bud Abbott tries to correct him, but Lou "proves" it.


    On a blackboard, he writes: . \begin{array}{ccc}1&4  \\ \times & 5 \\ \hline \end{array}

    He says, "Five time four is twenty": . \begin{array}{ccc}1&4 \\ \times & 5 \\ \hline 2 & 0 \end{array}

    Then "Five times one is five": . \begin{array}{ccc}1&4 \\ \times &5 \\ \hline 2&0 \\ & 5 \end{array}

    And before Bud can object, Lou draws the line and adds: / \begin{array}{cc}1&4 \\ \times & 5 \\ \hline 2 & 0 \\ & 5 \\ \hline 2 & 5 \end{array}
    "See?"


    Bud says, "You can't multiply like that! .What if you add five 14's?"

    Lou writes:. . \begin{array}{ccc}&1&4 \\ &1&4 \\ &1&4 \\ &1&4 \\+ &1&4 \\ \hline \end{array}


    Bud takes the chalk and adds up the right column: "4, 8, 12, 16, 20 ..."

    Lou pushes him aside and adds the down the left column: "21, 22, 23, 24, 25 !"

    And has: . \begin{array}{ccc}&1&4 \\ &1&4\\&1&4\\&1&4\\+&1&4\\ \hline & 2&5 \end{array}


    Bud complains again and asks "Okay, what is 25 divided by 5?"

    Lou write: . \begin{array}{cccc}&& - & - \\ 5 & ) & 2 & 5 \end{array}

    He says, "5 doesn't go into 2, but 5 goes into 5 once": . \begin{array}{cccc}&&& 1 \\ && - & - \\ 5 & ) & 2 & 5 \end{array}

    "One times five is five": . \begin{array}{cccc}&&&1 \\ && - & - \\ 5 & ) & 2 & 5 \\ &&&5 \end{array}

    "25 minus 5 is 20": . \begin{array}{cccc}&&&1 \\ && - & - \\ 5 & ) & 2 & 5 \\ &&& 5 \\ &&- & - \\ && 2 & 0 \end{array}

    "And 5 goes into 20 four times": . \begin{array}{ccccc}&&&1 & 4 \\ && - & - & - \\ 5 & ) & 2 & 5 \\  &&& 5 \\ & & - & - \\ & & 2 & 0 \\ && 2 & 0 \\ && - & - \\ \end{array}


    And Bud Abbott gives up . . .
    First time I heard about Abbot & Costello and they're funny! Yes what I just did does resemble one of their routines!
    play tennis
    Thanks
    Follow Math Help Forum on Facebook and Google+

  6. #6
    Member
    Joined
    Jan 2010
    Posts
    106
    Thanks
    2

    Re: Division problem, I need help please?

    This did remind me of something called "partial quotient division," but I don't want you to get confused so just take a look at it for fun at your leisure
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. division problem
    Posted in the Number Theory Forum
    Replies: 6
    Last Post: August 24th 2010, 05:02 PM
  2. Division Problem
    Posted in the Algebra Forum
    Replies: 2
    Last Post: May 29th 2010, 06:32 PM
  3. Division problem
    Posted in the Number Theory Forum
    Replies: 1
    Last Post: October 5th 2009, 07:29 PM
  4. Division problem with GCD
    Posted in the Number Theory Forum
    Replies: 4
    Last Post: February 4th 2007, 01:15 PM
  5. Division Problem
    Posted in the Number Theory Forum
    Replies: 5
    Last Post: January 19th 2007, 06:20 AM

Search Tags


/mathhelpforum @mathhelpforum