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Why does sqrtAB over B become sqrt AB

How do I make a post solved please

I know from using practical values this does happen but I don't understand were the extra B is cancelled out

I will try again with LaTex

THIS IS NOT CORRECT perhaps some could show me what is wrong

$\displaystyle frac\{\sqrt{AB}{B}$

I still can not work LaTex out ! . I have been trying for 5 hours !

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This was muy original question

Here is a paint jobbyAttachment 24173

Re: Why does sqrtAB over B become sqrt AB

Here is the correct LaTeX.

[TEX]\frac{\sqrt{AB}}{B} [/TEX] gives $\displaystyle \frac{\sqrt{AB}}{B} $.

$\displaystyle \frac{\sqrt{AB}}{B}=\sqrt{\frac{AB}{B^2}}=\sqrt{ \frac{A}{B}} $

BTW: The symbol $\displaystyle \boxed{\Sigma}$ on the tool bar gives the TeX wraps.

Re: Why does sqrtAB over B become sqrt AB

Hello, TeslaCoil!

Quote:

$\displaystyle \text{Why does }\:\frac{\sqrt{AB}}{B} \:=\:\sqrt{\frac{A}{B}}\;? $

$\displaystyle \frac{\sqrt{AB}}{B} \;=\;\frac{\sqrt{A}\cdot\sqrt{B}}{\sqrt{B}\cdot \sqrt{B}} \;=\; \frac{\sqrt{A}}{\sqrt{B}} \;=\;\sqrt{\frac{A}{B}} $

Re: Why does sqrtAB over B become sqrt AB

Don't forget to insert \ before any command (\frac, \int, \epsilon, \hspace).

For example, \frac{\sqrt{AB}}{B} gives $\displaystyle \frac{\sqrt{AB}}{B}$ and \sqrt{\frac{A}{B}} gives $\displaystyle \sqrt{\frac{A}{B}}$

Re: Why does sqrtAB over B become sqrt AB

Thanks that was a nice answer

Re: Why does sqrtAB over B become sqrt AB

That was a brilliant answer