What is the largest possible value of the product of two consecutive integers for which the square of the smaller integer minus 8 times the larger integer equals 25 ?(Ans=132 How would i solve this problem ?
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$\displaystyle n^{2}-8(n+1)=25$ gives you just two possible values for $\displaystyle n.$
n^{2}-8(n+1)=25 gives you just two possible values for n. I get two values -3 and 11 But 11 isnt the answer.
Hello, MikeNoob! I get two values -3 and 11 But 11 isn't the answer. Of course not! Read the question again: ."The largest product of two consecutive integers"
Read the question again: ."The largest product of two consecutive integers" Thanks for the tip 11*12
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