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Why does X/XA square root become square root of XR Ohms calculation

While explaining Ohms law to someone I realised I did not understand why http://mathhelpforum.com/image/png;b...AASUVORK5CYII= becomes http://mathhelpforum.com/image/png;b...AASUVORK5CYII=

I know , using practical numbers but I do not know how to prove it

Re: Why does X/XA square root become square root of XR Ohms calculation

Quote:

Originally Posted by

**TeslaCoil**

Thus

Re: Why does X/XA square root become square root of XR Ohms calculation

Your "E" is usually written as "U".

You know ? In this case, the derivation is simple and can be done like this:

Edit: Too slow.

Re: Why does X/XA square root become square root of XR Ohms calculation

Hello, TeslaCoil!

Can you handle fractional exponents?

Re: Why does X/XA square root become square root of XR Ohms calculation

Thanks very much and yes! I do remember doing exponents ( 1980's)

I am OK with the explanation __except where the fourth expression inverts P&R __- why does that work . I am OK with the fifth , sixth and seventh expressions

How does every one put mathematical symbols in here? Math pad and cut and past ?

BTW I was in Lexington MA. last October -nice area

Re: Why does X/XA square root become square root of XR Ohms calculation

Thank you

I was OK with the explanation until the R &P expressions were inverted - how does that work ... using practical figure I see it does but why

Sorry for using E instead of the SI unit V but the old "ohms magic circle" I was using for my friend showed E as ( energy) for volts and I did not want to confuse him at this point

The blind leading the blind comes to mind