Re: Mixture Type 2 - Problem

Wouldn't it just be:

you are adding water which has a 0% acid concentration

since you have 9gallons of acid, you want the total solution to be 36 gallons.

Add 36 - 27 gallons of water = 9 gallons.

Doing it in your table you have conc of water is 100%, but actually it's 0% as you're talking about the acid concentration.

so it would be

| Quantity | %age | Cal |

Initially | 27 | 1/3 | 9 |

addWater | x | 0 | 0 |

Required Solution | x+27 | 25% | 9 |

so (27+x)/4 = 9

x + 27 = 36

x= 9

Re: Mixture Type 2 - Problem

@Linalg123 You are absolutely correct. Thanks for pointing this out!!!.