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Math Help - physics, acceleration, physics problem

  1. #1
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    physics, acceleration, physics problem

    For a standard production car, the highest road-tested acceleration ever reported occured in 1993, when a Ford RS200 Evolution went from zero to 26.8 m/s (60 mi/h) in 3.275 s. Find the magnitude of the car's acceleration.
    displayed by
    m/s2
    Repeat, for another car which goes from zero to 60 mi/h in 4.940 s.
    calculated in m/s2

    trying to understand all the variable involved. thanks for any help you can give here. appreciate it.
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  2. #2
    MHF Contributor
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    These are all very similar. Get those three equations in your head. You will see them all.
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  3. #3
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    Quote Originally Posted by rcmango View Post
    For a standard production car, the highest road-tested acceleration ever reported occured in 1993, when a Ford RS200 Evolution went from zero to 26.8 m/s (60 mi/h) in 3.275 s. Find the magnitude of the car's acceleration.
    displayed by
    m/s2
    Repeat, for another car which goes from zero to 60 mi/h in 4.940 s.
    calculated in m/s2

    trying to understand all the variable involved. thanks for any help you can give here. appreciate it.
    [SUVAT! . Motion caused by..., or where acceleration is constant.]

    Evolution went from zero to 26.8 m/s (60 mi/h) in 3.275 s. Find the magnitude of the car's acceleration, displayed by m/s^2

    V final, Vf = Vo +at -----------(i)

    Given:
    Vo = 0
    Vf = 26.8 m/sec
    t = 3.275 sec

    Find a.

    26.8 = 0 +a(3.275)
    a = 26.8 /3.275 = 8.183 m/sec/sec -------------answer.

    Repeat, for another car which goes from zero to 60 mi/h in 4.940 s.
    calculated in m/s2


    Vo = 0
    Vf = 60mi/hr = 26.8m/sec
    t = 4.94 sec

    Vf = Vo +at
    26.8 = 0 +a(4.94)
    a = 26.8 /4.94 = 5.425 m/sec/sec --------------answer.
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  4. #4
    Forum Admin topsquark's Avatar
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    Quote Originally Posted by TKHunny View Post
    These are all very similar. Get those three equations in your head. You will see them all.
    Actually, I find that the following set of four equations is slightly more useful:
    x = x_0 + v_0t + \frac{1}{2}at^2

    v = v_0 + at

    v^2 = v_0^2 + 2a(x - x_0)

    This last equation is not strictly necessary, but including it means that students do not need to solve multiple equations in multiple unknowns (in 1-D motion, anyway.)
    x = x_0 + \left ( \frac{v_0 + v}{2} \right ) t

    -Dan
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