• September 26th 2007, 02:02 PM
rcmango
hey there, thought i would ask this in this section:

The Space Shuttle travels at a speed of about 7.70 103 m/s. The blink of an astronaut's eye lasts about 100 ms. How many football fields (length = 91.4 m) does the Shuttle cover in the blink of an eye?

so how many football fields?
whats a good equation to use also.

thanks.
• September 26th 2007, 02:13 PM
topsquark
Quote:

Originally Posted by rcmango
hey there, thought i would ask this in this section:

The Space Shuttle travels at a speed of about 7.70 103 m/s. The blink of an astronaut's eye lasts about 100 ms. How many football fields (length = 91.4 m) does the Shuttle cover in the blink of an eye?

so how many football fields?
whats a good equation to use also.

thanks.

Well, it's going to be a $d = vt$ problem, with a unit conversion at the end to convert meters to "football fields." But what is that speed for the shuttle? I would think 7.7 m/s to be far too small for the shuttle.

-Dan
• October 1st 2007, 12:30 AM
rcmango
ya, thats supposed to be 7.70 x 10^3 , thanks alot for the help.

so i think its: d = (7.7 x 10^3) * 103 m/s

..also, if i have to convert to meters at the end, then what is the distance units before the conversion?

thanks alot.
• October 1st 2007, 07:19 AM
topsquark
Quote:

Originally Posted by rcmango
ya, thats supposed to be 7.70 x 10^3 , thanks alot for the help.

so i think its: d = (7.7 x 10^3) * 103 m/s

..also, if i have to convert to meters at the end, then what is the distance units before the conversion?

thanks alot.

Your time is 100 ms. Thus

$d = (7.7 \times 10^3 ~m/s)(100 \times 10^{-3}~s)$

Your units for d are already in meters. You need to convert meters to football fields. (91.4 m = 1 football field.)

-Dan