(4 + 5i)^2 - (4 - 5i)^2
I have to write it in standard form a + bi
I am having trouble with this problem...I got an answer, but it is incorrect...could someone please help me?
(4 + 5i)^2 - (4 - 5i)^2
I have to write it in standard form a + bi
I am having trouble with this problem...I got an answer, but it is incorrect...could someone please help me?
Difference of two squares,
(4+5i + 4 - 5i)(4+5i - 4 + 5i) = 8*10i = 0 + 80i
If $\displaystyle z = x + yi$ then
$\displaystyle z^2 - \overline z ^2 = \left( {z + \overline z } \right)\left( {z - \overline z } \right) = \left( {2x} \right)\left( {2yi} \right)
$.
(4 + 5i)^2 - (4 - 5i)^2
I have to write it in standard form a + bi
I am having trouble with this problem...I got an answer, but it is incorrect...could someone please help me?
Thank you all very much! I've been working at that problem for the longest time but i just couldnt get it, but now i know what i was doing wrong! I forgot that it was squared when i copied it onto my paper