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Thread: simple force vector problem

  1. #1
    Senior Member furor celtica's Avatar
    May 2009

    simple force vector problem

    A child has weight 450 N. Whilst on a fairground ride the child is subject to a force P acting at 35° to the upward vertical, as shown in the diagram. Given that the resultant of P and the child’s weight acts horizontally,
    a. Find the magnitude of the resultant
    b. State the direction of the child’s acceleration
    c. Find the magnitude of the child’s acceleration

    My answers were the following
    a. 315 N (to 3 s.f.)
    b. The child’s acceleration is directed horizontally to the left
    c. 7.00 m(s^2) (to 3 s.f.)

    According to the textbook, my first two answers are correct, but the third is given as 6.86 m(s^2).
    How is this possible? a = F/m = 315 / 45 = 7 m(s^2). Did I miss something?
    Attached Thumbnails Attached Thumbnails simple force vector problem-untitled.png  
    Last edited by furor celtica; Jan 11th 2012 at 11:16 PM.
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  2. #2
    MHF Contributor MarkFL's Avatar
    Dec 2011
    St. Augustine, FL.

    Re: simple force vector problem

    You are using $\displaystyle g=10\frac{\text{m}}{\text{s}^2}$ while your textbook is using a more accurate value of $\displaystyle g=9.8\frac{\text{m}}{\text{s}^2}$.
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