# Thread: Physical Science Algebraic Problem Related to Motion

1. ## Physical Science Algebraic Problem Related to Motion

Would anybody be able to explain this problem and its equations for me? I don't understand it at ALL.

1)A ball is thrown upwards from a 100 m high cliff at 7.5 m/sec. If you ignore air resistance
A) What is its velocity after 7.0 sec?
B) How long until it is at its high point?
C) Where is it (Vertical height related to the ground) after 7.0 sec
D) When does it reach the ground?
E) What is the total distance moved?
F) WHat is the ball's speed just before hitting the ground?

2) A car accelerates uniformly in a straight line from rest at the rate of 2.3 m/s^2. What is the speed of the car after it has traveled 55m. Answer in meters per second.

Please, I really need somebody to explain this to me ASAP. I don't necessarily need the answers, but I NEED the equations! I just don't understand! And none of these are trick questions.

2. ## Re: Physical Science Algebraic Problem Related to Motion

Originally Posted by Psyche
Would anybody be able to explain this problem and its equations for me? I don't understand it at ALL.

1)A ball is thrown upwards from a 100 m high cliff at 7.5 m/sec. If you ignore air resistance
A) What is its velocity after 7.0 sec?
B) How long until it is at its high point?
C) Where is it (Vertical height related to the ground) after 7.0 sec
D) When does it reach the ground?
E) What is the total distance moved?
F) WHat is the ball's speed just before hitting the ground?

2) A car accelerates uniformly in a straight line from rest at the rate of 2.3 m/s^2. What is the speed of the car after it has traveled 55m. Answer in meters per second.

Please, I really need somebody to explain this to me ASAP. I don't necessarily need the answers, but I NEED the equations! I just don't understand! And none of these are trick questions.
Kinematics equations for uniformly accelerated motion in the vertical direction under the influence of gravity ...

$\displaystyle v = v_0 - gt$

$\displaystyle \Delta y = v_0 t - \frac{1}{2}gt^2$

$\displaystyle v_f^2 = v_0^2 -2g \Delta y$

3. ## Re: Physical Science Algebraic Problem Related to Motion

Okay. I know 1a goes with eq #1, but what about the others, and how would you plug the numbers in? I'm sorry. I'm so confused. Haha

4. ## Re: Physical Science Algebraic Problem Related to Motion

B) How long until it is at its high point?

$\displaystyle v = 0$ at the top of the ball's trajectory

C) Where is it (Vertical height related to the ground) after 7.0 sec

use the $\displaystyle \Delta y$ equation with $\displaystyle y_0 = 100 m$

D) When does it reach the ground?

set $\displaystyle \Delta y = -100$ , solve for t

E) What is the total distance moved?

2(displacement up) + 100

F) WHat is the ball's speed just before hitting the ground?

|v| when it hits the ground (use the solution for part D)

6. ## Re: Physical Science Algebraic Problem Related to Motion

Originally Posted by Psyche
go to the link and learn about motion in one dimension ...

http://www.physicsclassroom.com/class/1DKin/U1L6a.cfm

7. ## Re: Physical Science Algebraic Problem Related to Motion

Well i found this site is very useful defined the theory
Motion in One Dimension

8. ## Re: Physical Science Algebraic Problem Related to Motion

Originally Posted by Psyche
We can take the third kinematics equations given by skeeter and modify it a bit to meet our needs. We are told the car begins at rest ($\displaystyle v_0=0$) and accelerates uniformly at $\displaystyle a=2.3\text{ }\frac{\text{m}}{\text{s}^2}$ and undergoes a displacement of $\displaystyle \Delta x=55\text{ m}$, so the equation becomes:

$\displaystyle v_f^2=2a\Delta x$

$\displaystyle \left|v_f\right|=\sqrt{2a\Delta x}$

Now just plug in the given data to find the magnitude of the final velocity vector, which is the speed.

Suppose we did not have the formula handy. We can find it by reasoning as follows:

We know the distance traveled is the average velocity times the time traveled:

$\displaystyle \Delta x=\frac{v_0+v_f}{2}t\:\therefore\:t=\frac{2\Delta x}{v_f+v_0}$

We know uniform acceleration is the change in velocity divided by the change in time:

$\displaystyle a=\frac{v_f-v_0}{t}\:\therefore\:t=\frac{v_f-v_0}{a}$

We have 2 expression for time t, so equate them to get:

$\displaystyle \frac{2\Delta x}{v_f+v_0}=\frac{v_f-v_0}{a}$

Cross-multiply:

$\displaystyle v_f^2-v_0^2=2a\Delta x$

$\displaystyle v_f^2=2a\Delta x+v_0^2$