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Math Help - Finding parallel unit vector

  1. #1
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    Finding parallel unit vector

    Problem: A unit vector parallel to vector V = (2, -3, 6) is ?

    Answer is (-.29, .43, -.85)

    Thanks. I thought to find a parallel vector you have to multiply through by the same number, so I chose the answer (-2, 3, -6)
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  2. #2
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    Re: Finding parallel unit vector

    Quote Originally Posted by benny92000 View Post
    Problem: A unit vector parallel to vector V = (2, -3, 6) is ? Answer is (-.29, .43, -.85)
    Find the length, \|V\|=\sqrt{2^2+(-3)^2+6^2}=7.

    Now divide \left\langle {\frac{2}{7},\frac{{ - 3}}{7},\frac{6}{7}} \right\rangle .

    There is your parallel unit vector.
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    Re: Finding parallel unit vector

    Ok, and can the length be -7, as well? As in divide through by -7 to find the right answer? That is what my book says, so I just wanted to verify this.
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    Re: Finding parallel unit vector

    Quote Originally Posted by benny92000 View Post
    Ok, and can the length be -7, as well? As in divide through by -7 to find the right answer? That is what my book says, so I just wanted to verify this.
    Length is never negative.
    However, dividing by -7 also gives a unit vector parallel to the given vector.
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