Okay, this one I've looked at and I don't think I'll figure it out before someone posts. :)
Large cockroaches can attain a speed of 2.20 m/s in short bursts. Suppose you turn on the light in a cheap motel and see one scurrying directly away from you at a constant speed 2.20 m/s as you move toward it at a speed of 0.800 m/s.
If you start a distance 0.980 m behind it, what minimum constant acceleration would you need to catch up with it when it has traveled a distance 2.10 m, just short of safety under a counter?
I think since I'm not given a time, I'll have to use the equation that doesn't use it (obvious... er, right?).
Okay, following your work I end up with .
I did make a boo-boo when I plugged into my calculator. (0.08 is not quite the same as 0.8!) However, I'm now getting 5.08 m/s^2. Tolerably close, but there may be an error in your work somewhere as well. (Unless you didn't do the whole problem at once and you did it in steps, rounding as you went... That would account for the discrepency.)
Originally Posted by cinder