Another that has stumpted me... (sorri about the typos ticbol)
P(x) = x^3 - 3x + 2
So i find that P(2) is a value as it = zero.
So I have:
P(x) = (x-2)(ax^2 + bx + 1) (typo)
Then I divide x-2 / x^3 - 3x + 2
But I get x^2 +2x + 1 Remainder 4!!
So what went wrong, how do you factorise the equation?! Need help!