Math Project

• Sep 5th 2007, 07:24 AM
susie44
Math Project
Ok, I have a math project. We have to pick a month (I chose November which has 30 days) and make an equation for each of those days. These are our variables that we can use only once per equation, and we have to use each variable once per equation.

A= 1 B= -2 C= 3 D= -4

I need help creating the equations, the only numbers that I need now are: 13, 14, 16, 18, 19, 20, 27, 28, and 29.

We can only use the order of operations (Parenthesis, Exponents, Multiplication, Division, Addition and Subtraction)

EXAMPLE:

d-b+axc= 1

Thanks so much!!
• Sep 5th 2007, 07:25 AM
susie44
Oh
Oh and the answer cannot be negative.
• Sep 5th 2007, 07:32 AM
topsquark
Quote:

Originally Posted by susie44
Ok, I have a math project. We have to pick a month (I chose November which has 30 days) and make an equation for each of those days. These are our variables that we can use only once per equation, and we have to use each variable once per equation.

A= 1 B= -2 C= 3 D= -4

I need help creating the equations, the only numbers that I need now are: 9, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 26, 27, 28, 29, and 30.

We can only use the order of operations (Parenthesis, Exponents, Multiplication, Division, Addition and Subtraction)

EXAMPLE:

d-b+axc= 1

Thanks so much!!

You mean something like
$b - a - c \times d = 9$?

-Dan
• Sep 5th 2007, 07:38 AM
susie44
yes!!
yes thank you so much! do you know anymore?
• Sep 5th 2007, 08:42 AM
red_dog
$-a+b-cd=13$
$-ab-cd=14$
$a-b-cd=15$
$d^{a+b+c}=16$
$(a-d)c-b=17$
$(-b-d)ac=18$
$(-b-d)c+a=19$
$(c-b)(a-d)=20$
$(c-d)(a-b)=21$
$(a-d)^{-b}-c=22$
$(-cd+a)(-b)=26$
$c^{-b}(-a-d)=27$
$(a-d)^{-b}+c=28$
$(-b)^{a-d}-c=29$
$(a-d)(-bc)=30$
• Sep 5th 2007, 09:24 AM
susie44
Quote:

Originally Posted by red_dog
$-a+b-cd=13$
$-ab-cd=14$
$a-b-cd=15$
$d^{a+b+c}=16$
$(a-d)c-b=17$
$(-b-d)ac=18$
$(-b-d)c+a=19$
$(c-b)(a-d)=20$
$(c-d)(a-b)=21$
$(a-d)^{-b}-c=22$
$(-cd+a)(-b)=26$
$c^{-b}(-a-d)=27$
$(a-d)^{-b}+c=28$
$(-b)^{a-d}-c=29$
$(a-d)(-bc)=30$

thanks, some of these were very helpful. but you can't change the value of the variable, meaning you can't make A into -A. thanks thouhg :D
• Sep 5th 2007, 09:37 AM
Jhevon
Quote:

Originally Posted by susie44
thanks, some of these were very helpful. but you can't change the value of the variable, meaning you can't make A into -A. thanks thouhg :D

that makes no sense. you listed "subtraction" as one of your allowed operations. so saying -A is just saying subtract A or possibly the negative of A, which we can make it work anyway

which of red_dog's answers do you have a problem with? the ones with the powers?
• Sep 5th 2007, 10:35 AM
susie44
sorry
Quote:

Originally Posted by Jhevon
that makes no sense. you listed "subtraction" as one of your allowed operations. so saying -A is just saying subtract A or possibly the negative of A, which we can make it work anyway

which of red_dog's answers do you have a problem with? the ones with the powers?

yeah i realized that after i posted the reply, im sorry. idk why but i always forget that rule and i ran back through the problems and found some more that worked :D
thanks :p
• Sep 5th 2007, 10:36 AM
susie44
and yes, the ones with the powers didnt work on my calculator (its an advanced one) and then i tried it manually, but it didn't work out either. but still, some did work (even though they didnt come out to the answer he said)