Communication channel: baud rate, bit rate, etc.

Quote:

The communication channel (ideally) "lets through" frequencies from 450 Hz to 3250 Hz and has a signal / noise (S/N) ratio of 42 dB.

**(a)** How many

__signal elements per second__ (bauds) is it possible to transfer over this channel?

**(b)** What is the

__max. bit rate__ over this channel?

**(c)** How do results from

**(a)** and

**(b)** influence

__modem's properties__?

Please, help me correct my "answers". Thank you.

**(a)** ? Reasoning: you only get 1 crest and 1 trough, hence this theoretical limit? So, if my reasoning is sound, the __baud rate__

**(b)** Depends on number of states each baud (signal) can have. E.g. if a signal can be in 4 states, then each baud "carries" 2 bits, and the __max. bit rate__ = 2 * __baud rate__.

As we're given the S/N ratio, we can use the equation for the channel capacity:

**(c)** We divide the __max. bit rate__ from **(b)** by the __baud rate__ from **(a)** and get the number of bits/baud? That's all? (Wondering)

PS: I see that, instead of repairing the [tex] tag, you've just added the [TEX]. (Rofl)

Re: Communication channel: baud rate, bit rate, etc.

The equation for channel capacity of a band limited channel with bandwidth W is where is SNR. But this SNR is not in dB. So substitute 10^4.2 for in the equation to get the maximum bit rate.

Re: Communication channel: baud rate, bit rate, etc.

Is answer to **(a)** correct?

And what would you add to my (incomplete) answer to **(c)**:

For **(b)**, I got the __max. bit rate__ of . So, given the theoretical limit of from **(a)**, what is the answer to **(c)**? Is it, that (if we ever wanted to achieve theoretical throughput) the signals *should *have possible states and we would hence have ?