Thread: N < B < P(N) ?? (logic set and theory)

hi ,
as of the title , is there a B that N < B < P(N) ??

N are the complete numbers set.
P(N) is { x | x in N } ??

if there is , would please give an example , else proof that there isn't , thanks a lot ?

Originally Posted by mIXpRo

hi ,
as of the title , is there a B that N < B < P(N) ??

N are the complete numbers set.
P(N) is { x | x in N } ??

if there is , would please give an example , else proof that there isn't , thanks a lot ?

You mean to Continuum hypothesis - Wikipedia, the free encyclopedia?

thanks that what i was looking for .