hi ,

as of the title , is there a B that N < B < P(N) ??

N are the complete numbers set.

P(N) is { x | x in N } ??

if there is , would please give an example , else proof that there isn't , thanks a lot ?

Printable View

- July 2nd 2011, 04:09 AMmIXpRoN < B < P(N) ?? (logic set and theory)
hi ,

as of the title , is there a B that N < B < P(N) ??

N are the complete numbers set.

P(N) is { x | x in N } ??

if there is , would please give an example , else proof that there isn't , thanks a lot ? - July 2nd 2011, 04:33 AMAlso sprach ZarathustraRe: N < B < P(N) ?? (logic set and theory)
- July 2nd 2011, 04:39 AMmIXpRoRe: N < B < P(N) ?? (logic set and theory)
thanks that what i was looking for :D .