Hi
I need some clarification on this question
A light elastic string of natural length 50 cm and modulus 20 N has one end fastened to O on a smooth horizontal table. The other end has a particle of mass 0.4 kg attached to it and the particle is released from rest at a distance 60 cm from O. Find the time it takes to reach O.
While the string is stretched
T=kx/l
=20x/0.5
=40x
40x=-.4a
So,a = -100x
w=10
T=2pi/10 =pi/5
I get stuck from here. Can anyone help please? ThanksHi
I need some clarification on this question
A light elastic string of natural length 50 cm and modulus 20 N has one end fastened to O on a smooth horizontal table. The other end has a particle of mass 0.4 kg attached to it and the particle is released from rest at a distance 60 cm from O. Find the time it takes to reach O.
While the string is stretched
T=kx/l
=20x/0.5
=40x
40x=-.4a
So,a = -100x
w=10
T=2pi/10 =pi/5
I get stuck from here. Can anyone help please? Thanks


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