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Math Help - A simple problem, two factors

  1. #1
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    A simple problem, two factors

    Rehearsing a bit of math I come across this problem I've got a hard time to get a grip on.
    _______
    A person shoots at a barrel, two seconds later he hears the bullet hit the barrel. The speed of sound is 340m/s and the average speed of the bullet is 650m/s.

    What is the distance between the shooter and the barrel?
    --------
    Thank you for your help

    Edit: Maybe the distance can be expressed as x and ...?
    Last edited by λιεҗąиđŗ; August 30th 2007 at 06:43 AM. Reason: Progress
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  2. #2
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    Hello, λιεҗąиđŗ!

    A person shoots at a barrel.
    Two seconds later he hears the bullet hit the barrel.
    The speed of sound is 340m/s and the average speed of the bullet is 650m/s.

    What is the distance between the shooter and the barrel?
    We know that: . \text{Distance } = \text{Speed }\times \text{Time}\quad\Rightarrow\quad T \:=\:\frac{D}{S}


    Let x = distance from the shooter to the barrel (in meters).

    . . At 650 m/s, the bullet takes: . \frac{x}{650} seconds to reach the barrel.

    . . At 340 m/s, the sound takes: . \frac{x}{340} seconds to reach the shooter.

    Since the total time is 2 seconds, we have: . \frac{x}{650} + \frac{x}{340} \:=\:2

    . . Now solve for x . . .

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  3. #3
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    Could the two x's be merged? Only way I see to make some progress?

    Btw, why does my text come out as red? lol.

    Edit: On second thought, should this thread be closed and a new one created for purely solving the equation?
    Last edited by λιεҗąиđŗ; August 30th 2007 at 08:59 AM. Reason: Syntax error
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  4. #4
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    Heloo, λιεҗąиđŗ!

    Could the two x's be merged? . . . . Of course!
    Do you need an Algebra review?


    Multiply through by the LCD: 2210

    . . 34x + 65x \;=\;4420\quad\Rightarrow\quad 99x \;=\;4420

    Therefore: . x \;=\;\frac{4420}{99} \;=\;44.\overline{64}

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