did this help?Object is projected from a speed of V and an angle of Θ
Horizontal displacement is 15m ,vertical displacement is 5m
Find V and Tan Θ
x=V cos Θ*t
t=x/V cos Θ
y=v Sin Θ*t-g/2*t²
instead of using 't' you should have used 't/2' in the above eqn. do you see why?
from first equation y=V sinΘ(x/V cosΘ)-g/2*(x/v cosΘ)²
5=V sin Θ(15/V cos Θ)-g/2 *(15/V cosΘ)² <<<Stuck!!!!
Books says 12.5 , 4/3