Object is projected from a velocity of 18 m/s and angle of 60 degrees .

take g=10

what is the flying time , Horizontal distance and the maximum height of the object ?

this is what I did which gave the wrong answers

v=u+at

0=v sin Θ-gt/2

t=2v*sin Θ/g

t=2*18 sin 60/10

t=1.8*√3/2

t=1.56

-->

s=18*cos 60*1.56 =14m

(up)

s=18*√3/2 - 5(1.56)²

=3.42m

Those are not answers .help

thanks

book says 0.77s << I think time is wrong in the book:

Horizontal distance 28.02m (i got 14)

maximum height 12.15m (i got 3.42)