8kg object is dragged 25m distance on a 30 degrees
inclined plate.if the friction coefficient is 0.2 between the plate and the object,
what is the work done agaisnt the friciton and the gravity?
I think i found the work against the frictions which is wrong and NOT the answer at the behind of book
80N*Sin 30 =40N <<is the force on the inclined plate of the 80N object
so the Friction is 0.2*40 =8N
so work against the friction is 25*8 =200N which is wrong
what is da correct answer
work agianst the Gravity is:
sin 30*25 =12.5 m which is vertical distance traveled.
so Work=F*D =80N*12.5m = 1000