8kg object is dragged 25m distance on a 30 degrees

inclined plate.if the friction coefficient is 0.2 between the plate and the object,

what is the work done agaisnt the friciton and the gravity?

I think i found the work against the frictions which is wrong and NOT the answer at the behind of book

80N*Sin 30 =40N <<is the force on the inclined plate of the 80N object

so the Friction is 0.2*40 =8N

so work against the friction is 25*8 =200N which is wrong

what is da correct answer

work agianst the Gravity is:

sin 30*25 =12.5 m which is vertical distance traveled.

so Work=F*D =80N*12.5m = 1000