http://oi51.tinypic.com/2nk2qtg.jpg

I was able to find I1:

simplified and got total resistance=10/3 and V=10(coz parallel)

by putting V=IR

I got 10=I(10/3)

I=3A

How to find the I2?I think my I1 is wrong too.

thanks for reasing.

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- May 15th 2011, 10:04 PMsilvercatsHow to solve this simple circuit ?
http://oi51.tinypic.com/2nk2qtg.jpg

I was able to find I1:

simplified and got total resistance=10/3 and V=10(coz parallel)

by putting V=IR

I got 10=I(10/3)

I=3A

How to find the I2?I think my I1 is wrong too.

thanks for reasing. - May 16th 2011, 03:32 AMBAdhi
Have you learned a theory called Kirchhoff's(not sure about the spellings) two laws?

- May 16th 2011, 05:55 AMsilvercats
- May 16th 2011, 07:11 PMBAdhi
Here you have to use the Kirchoff's first law (or the current law), which is on any joint of the circuit, $\displaystyle \sigma I=0$.

From this you'll get the current flowing through the middle resistor as $\displaystyle I_1-I_2$

now use the Kirchoff's Voltage law which is on any closed circuit, $\displaystyle \sigma E=0$

add this equation to two closed circuits to find $\displaystyle I_1$ and $\displaystyle I_2$ - May 16th 2011, 07:32 PMsilvercats
I know that ΣE=ΣIR(that is the kirchhoff's law I guess?) thing.Did according to that and never got the answer in the book .I don't understand above thing too ups

- May 16th 2011, 08:33 PMBAdhi
- May 16th 2011, 08:47 PMsilvercats
parallel 4Ω and 2Ω: (1/4)+(1/2)=1/R =4/3Ω

that 4/3Ω and left side's 2Ω are =4/3 + 2 =10/3Ω

because there are two parallel batteries ,10v and 10v =10 ( <<< this is wrong i think)

and

by putting V=IR

I got 10=I(10/3)

I=3A - May 16th 2011, 09:12 PMBAdhi
you cannot simplify resistors that easily, refer Kirchhoff's circuit laws and your text books, I guess you've already been taught about this laws