How to find the velocity of the train using the graph below?

**silvercats** · May 15th 2011, 05:43 AM

http://oi52.tinypic.com/1zg7oxy.jpg

I got few equations but not correct I guess
(1/2)v(60+60-(t1+t3))=432

1/3=v/t1
and 1=v/t3

after manipulating the answers I get a way off answer which is not even close to the answer in the book.explained details are appreciated

**alexmahone** · May 15th 2011, 05:59 AM

Originally Posted by silvercats

http://oi52.tinypic.com/1zg7oxy.jpg

I got few equations but not correct I guess
(1/2)v(60+60-(t1+t3))=432

1/3=v/t1
and 1=v/t3

after manipulating the answers I get a way off answer which is not even close to the answer in the book.explained details are appreciated

Your method seems right.

$\frac{1}{2}(120-3v-v)=432$

$v(60-2v)=432$

$30v-v^2=216$

$v^2-30v+216=0$

$(v-18)(v-12)=0$

$v=18\ or\ 12$

But $v=18 \implies t_1=54\ and\ t_3=18$ (Contradiction since the times add up to more than 60.)

Therefore, $v=12$

**silvercats** · May 15th 2011, 09:34 PM

That is great.thanks!

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